Re: [idvdevelopers] ISL scripting

• To: "Stuart Wier" <wier@xxxxxxxxxx>, <idvdevelopers@xxxxxxxxxxxxxxxx>
• Subject: Re: [idvdevelopers] ISL scripting
• From: "Jun Chen" <jchen@xxxxxxxxxx>
• Date: Tue, 6 Apr 2010 10:49:37 -0700

Possible can be done using python scripting?

-jun

-----Original Message-----
From: Stuart Wier [mailto:wier@xxxxxxxxxx] 
Sent: Tuesday, April 06, 2010 10:20 AM
To: Jun Chen; idvdevelopers@xxxxxxxxxxxxxxxx
Subject: Re: [idvdevelopers] ISL scripting



Jun Chen wrote:
> Following that example isl file multiplefiles.isl:
> 
> <isl offscreen="false">
>    <fileset  pattern=".*\.nc">
>      <echo message="File: ${file}"/>
>      <bundle file="${islpath}/test.xidv">
> <!-- This sets the data file in the bundle to the ${file} -->
>       <setfiles datasource=".*" file="${file}"/>
>      </bundle>
>      <pause seconds="20"/>
>    </fileset>
> </isl>
> 
> I want to dynamically generate each image file based on each file
> ${file}, but that file contains path and link from a location I only
> have read permission, my question is:
> 
> How can I extract the (only) file name (without file extension) from
> ${file}?
> Say ${file}="/myserver/mydirectory/myfile1.nc"
> 
> Is there any way I can extract just myfile1 from ${file}?
> 
> So I can add:
> 
> <image file="${islpath}/${myfilename}.png" />
> 
> Above, ${myfilename} should change corresponding to ${file}
> 
> Please help.
> 
> I am new to IDV, and found it's very useful, but poor documentation.
> 
> 

Use shell scripting to create your file names and then use the shell to
write your isl file dynamically.

ISL is not a replacement for the shell.

• Follow-Ups:
  • Re: [idvdevelopers] ISL scripting
    • From: Chris Burghart
  • Re: [idvdevelopers] ISL scripting
    • From: Tom Whittaker

• References:
  • [idvdevelopers] ISL scripting
    • From: Jun Chen
  • Re: [idvdevelopers] ISL scripting
    • From: Stuart Wier