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Re: [netcdfgroup] Need help to convert .csv files to netCDF files

Greetings Dumindu!

We at Unidata have been working on a tool called Rosetta that may be of
interest:

http://www.unidata.ucar.edu/software/rosetta/

Rosetta is a web based data translator. Currently there is a wizard based
interface which guides users through the process of parsing a sample data
file as well as guiding users through the process of supplying CF metadata.
Once this information is collected, Rosetta produces a CF 1.6
complient netCDF file and a Rosetta template. The template can then be used
to batch process other csv files with the same structure and metadata.

If this interests you, I invite you to check out some of the presentations
available on the Rosetta page (link above). Rosetta is currently in a
limited testing period, but your use case would be perfect to kicking the
tires on a large scale. If you're interested, please contact us at
support-rosetta@xxxxxxxxxxxxxxxx.

Cheers!

Sean

On Thursday, March 5, 2015, Dumindu Jayasekera <
d.jayasekera@xxxxxxxxxxxxxxxxx> wrote:

> Hi,
>
> I need to convert .csv file (see the attached file) which has lat, long,
> precip to netCDF? I have over two thousands of these .csv files in 15
> folders.
>
> Can somebody help to do the conversion?
>
> I saw the following posting to use in Ferret I new to Ferret. Can somebody
> guide me how to use the script in Ferret. Also, I could not found the
> script mention in the website. Can I use a similar approach for the
> attached .csv file.
>
> http://permalink.gmane.org/gmane.comp.lib.netcdf/1136
>
> Any help is appreciated.
>
> Thanks,
>
> Dumindu.
>
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