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Hi Steve, thanks for your immediate answer. Unfortunately I am not familiar to Delaunay Triangulation. Ok, I understand the Delaunay Triangulation breaks up my set of points in a structure with triangles. I thinks this happens somewhere in Irregular2D set. But how are the triangles organized? What is the method getNeighbours doing? I am putting an 2D-array of floats in the the Irregular2D set, what is the int[][] array in get Neighbours? Does it somehow specify the indices, which floats cooresponds to an triangle? Where can I find more Information about Irregular2D set? Thanks again for your help Desiree o------------------------------------------------------------------------o | Desiree Hilbring Institut fuer Photogrammetrie und Fernerkundung | | Universitaet Karlsruhe, Germany | | | | email: hilbring@xxxxxxxxxxxxxxxxxxxx | | # 0721 6083676 | o------------------------------------------------------------------------o On Thu, 22 Feb 2001, Steve Emmerson wrote: > Desiree, > > Your question is really one for Bill Hibbard, the developer of VisAD. > Unfortunately, he's travelling, so the rest of us will try to help. > > Unfortunately again, I'm not familiar with triangulation algorithms > (though I am familiar with VisAD). If I had to guess, I'd suggest > that you create the Irregular2DSet with a Delaunay triagulation that > you explicitly obtain from the Delaunay.factory(...) method. You > should then be able to use the fields in the triagulation (Edges, > Tri, Vertices, etc.) to discover in which triangle a point resides > (assuming you're familiar with Delaunay triagulation). For help on > this, you might want to look at the getNeighbors(...) method in class > IrregularSet. > > Hope this helps. > > Regards, > Steve Emmerson <http://www.unidata.ucar.edu> > > >Date: Thu, 22 Feb 2001 16:16:54 +0100 (MET) > >From: Desiree Hilbring <hilbring@xxxxxxxxxxxxxxxxxxxx> > >Organization: UCAR/Unidata > >To: visad-list@xxxxxxxxxxxxx > >Subject: Point in Triangle > >Keywords: 200102221519.f1MFJML15618 > > > > Hi, > > > > I have a given set of 3D-point and the x,y-coordinates of one point > > somewhere in my set of points. I > > want to interpolate the height of the point. > > I want to add this point in my set and use the Delaunay-Triangulation of > > VisAD. > > Without this extra point the Delaunay Triangulation is working fine. > > > > RealType x = RealType.getRealType("x"); > > RealType y = RealType.getRealType("y"); > > RealType height = RealType.getRealType("height"); > > try { > > RealTupleType xy = new RealTupleType(x, y); > > FunctionType terrain_type = new FunctionType(xy, height); > > Irregular2DSet set = new Irregular2DSet(xy,new float[][] > > {eastValues,northValues}); > > FlatField terrain = new FlatField(terrain_type, set); > > terrain.setSamples(new float[][] {heightValues}); > > > > display = new DisplayImplJ3D("display1"); > > ScalarMap hoxmap = new ScalarMap(x, Display.XAxis); > > ScalarMap reymap = new ScalarMap(y, Display.YAxis); > > ScalarMap heightmap = new ScalarMap(height, Display.ZAxis); > > > > display.addMap(hoxmap); > > display.addMap(reymap); > > display.addMap(heightmap); > > > > hoxmap.setRange(-1.0, 1.0); > > reymap.setRange(-1.0, 1.0); > > heightmap.setRange(-1.0, 1.0); > > > > DataReferenceImpl data_ref = new > > DataReferenceImpl("data_ref"); > > data_ref.setData( terrain ); > > renderer = new DefaultRendererJ3D(); > > display.addReferences(renderer,data_ref); > > display.addDisplayListener(listener); > > } > > catch (VisADException ve) { > > System.out.println("VisAd TupleType Exception"); > > } > > catch (RemoteException re) { > > System.out.println("RemoteExcpetion"); > > } > > > > How can I find the triangle in which the point belongs to? > > Are there some standard geometric algorithms to achieve that? > > Where do I have to look at. > > > > Thanks for your help in advance > > > > Desiree > > > > > > > > o------------------------------------------------------------------------o > > | Desiree Hilbring Institut fuer Photogrammetrie und Fernerkundung | > > | Universitaet Karlsruhe, Germany | > > | | > > | email: hilbring@xxxxxxxxxxxxxxxxxxxx | > > | # 0721 6083676 > > | > > o------------------------------------------------------------------------o >
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