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> The x-values are in samples[0] and the y-values are in samples[1]; > > Let you DEM be > > 3.3 x x > north 2.7 x > > 1.3 x x x > 0.2 0.3 1.1 1.2 > east > > Sampled points are represented bx "x". > > You've got lenX = 3, lenY = 2, and, thus, must input 6 pairs of > coordinates. > So, samples is (something like): samples[0]={0.2,1.1,1.2, 0.2,0.3,1.2}; > // east, or x values > and samples[1]={1.3,1.3,1.3, 3.3,2.7,3.3}; // > north, or y values > Hi Ugo, I am getting confused, I tried to implement the above, //double[][] coords = new double[2][east.length]; coords[0] = new double[east.length]; coords[1] = new double[north.length]; for (int i=0;i<coords[0].length;i++) { coords[0][i]=east[i]; coords[1][i]=north[i]; } for (int j=0;j<coords[0].length;j++) { System.out.println("e "+coords[0][j]); } for (int j=0;j<coords[1].length;j++) { System.out.println("n "+coords[1][j]); } and they look like your samples[0] and samples[1] now you are saying i have an array double[2][east*north], that would be 3*4 in your example? How would I fill this array? Sorry, I am just feeling stupid, I do not get that! Thanks Desiree
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