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Hi Tom, thanks for your help! So... --- // Create the grid float[][] grid = new float[2][xCoordinates.length * yCoordinates.length]; int count = 0; for (int j=0; j<yCoordinates.length; j++) { for (int i=0; i<xCoordinates.length; i++) { grid[0][count] = xCoordinates[i]; grid[1][count] = yCoordinates[j]; count++; } } Gridded2DSet set = null; set = new Gridded2DSet(this.cubeTuple, grid, xCoordinates.length, yCoordinates.length); --- ... does the job. And... --- for (int i=0; i<xCoordinates.length; i++) { for (int j=0; j<yCoordinates.length; j++) { grid[0][count] = xCoordinates[i]; grid[1][count] = yCoordinates[j]; count++; } } --- ... does not. Best wishes, Eugen -----Ursprüngliche Nachricht----- Von: Tom Rink [mailto:rink@xxxxxxxxxxxxx] Gesendet: Montag, 13. Februar 2006 16:44 An: STAAB, Eugen Cc: visad@xxxxxxxxxxxxxxxx Betreff: Re: Gidded2DSet Hi Eugen, The first dimension in your float[2][3*4] array should be the fastest varying dimension (VisAD convention), so this should work if you invert the [3*4] arrays. Tom STAAB, Eugen wrote: >Hi there, > >are only quadratic Gridded2DSets allowed? >Or: Why is a Gridded2DSet with the following coordinates not valid? > >new float[]{0,6,9} // X-Coordinates >new float[]{0,7,8,9} // Y-Coordinates > >Which makes up the following float[2][3*4] Array of Coordinates: >[[0.0, 0.0, 0.0, 0.0, 6.0, 6.0, 6.0, 6.0, 9.0, 9.0, 9.0, 9.0], >[0.0, 7.0, 8.0, 9.0, 0.0, 7.0, 8.0, 9.0, 0.0, 7.0, 8.0, 9.0]] > > >A VisadException Exception is thrown in the Samples consistency test >of the Gridded2DSet class, line 171 ("Gridded2DSet: samples do not form a >valid grid (0,0)"). > >The values of the variables at the point of the thrown expection are: > >i= 0 >j= 0 > >xpos= -42.0 > >w1= -42.0 >w2= 12.0 >w3= 54.0 >w4= 0.0 >v00= float[2] (id=38) > [0]= 0.0 > [1]= 0.0 >v10= float[2] (id=39) > [0]= 0.0 > [1]= 7.0 >v01= float[2] (id=40) > [0]= 0.0 > [1]= 9.0 >v11= float[2] (id=41) > [0]= 6.0 > [1]= 0.0 > >So, w2, w3 and w4 would cause the exception to be thrown. >Is this intended? > > >Thanks for your help! > > >Best wishes, >Eugen > > >
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